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FractionRush AQA GCSE Physics 4.2
AQA GCSE Physics 4.2

Current, Voltage & Resistance

Master Ohm's Law — the fundamental relationship between voltage, current and resistance — and learn how to measure these quantities in real circuits.

⚡ Define electric current and state its unit (ampere, A)
🔋 Define potential difference (voltage) and state its unit (volt, V)
🔩 Define resistance and state its unit (ohm, Ω)
📐 Apply Ohm's Law: V = IR to solve problems
🔬 Describe how to measure current (ammeter) and voltage (voltmeter) in a circuit
📊 Interpret V–I graphs for ohmic and non-ohmic components

⚡ Electric Current

Electric current is the rate of flow of electric charge. In a metal conductor, current is due to the movement of free (delocalised) electrons through the material.

When a battery or power supply is connected to a circuit, it creates a potential difference that drives electrons around the circuit. Although electrons actually flow from the negative terminal to the positive terminal, by convention we say conventional current flows from positive to negative. This historical convention is universally used in circuit diagrams.

I = Q ÷ t
Current (A) = Charge (C) ÷ Time (s)
QuantitySymbolUnitUnit Symbol
CurrentIAmpereA
ChargeQCoulombC
TimetSeconds
One ampere means one coulomb of charge passes a point every second. A typical household lamp carries about 0.5 A; a phone charger about 1–2 A.

Current is measured using an ammeter. An ammeter must always be connected in series with the component being investigated, so that all the current flows through it. An ideal ammeter has zero resistance, so it does not alter the current in the circuit.

🔋 Potential Difference (Voltage)

Potential difference (p.d.), commonly called voltage, is the energy transferred per unit charge as charges move between two points in a circuit.

You can think of potential difference as the "electrical pressure" that pushes charges around a circuit. A 9 V battery transfers 9 joules of energy to every coulomb of charge that passes through it. The greater the potential difference across a component, the more energy is transferred by each unit of charge passing through it.

V = W ÷ Q
Potential Difference (V) = Energy Transferred (J) ÷ Charge (C)
QuantitySymbolUnitUnit Symbol
Potential DifferenceVVoltV
Energy TransferredWJouleJ
ChargeQCoulombC
One volt means one joule of energy is transferred per coulomb of charge.

Potential difference is measured using a voltmeter. A voltmeter must always be connected in parallel across the component, so it samples the voltage without diverting significant current away from the main circuit. An ideal voltmeter has infinite resistance.

🔩 Resistance

Resistance is a measure of how much a component opposes the flow of electric current. The higher the resistance, the harder it is for current to flow.

Resistance arises because free electrons collide with the fixed positive ions of the metal lattice as they move through the conductor. Each collision transfers kinetic energy to the ions, causing the material to heat up — this is the basis of resistive heating in devices like toasters and electric heaters.

Factors that affect the resistance of a wire include:

QuantitySymbolUnitUnit Symbol
ResistanceROhmΩ
Potential DifferenceVVoltV
CurrentIAmpereA
Resistance = potential difference ÷ current. If a component has a resistance of 1 Ω, a potential difference of 1 V drives a current of 1 A through it.

📐 Ohm's Law: V = IR

Ohm's Law states that the current through a conductor is directly proportional to the potential difference across it, provided the temperature remains constant.
V = I × R
Potential Difference (V) = Current (A) × Resistance (Ω)

This equation can be rearranged to find any of the three quantities:

I = V ÷ R     R = V ÷ I

A component that obeys Ohm's Law is called an ohmic conductor. For an ohmic conductor, a graph of V against I is a straight line through the origin. The gradient of an I–V graph (I on y-axis, V on x-axis) equals 1/R.

Non-ohmic conductors do not obey Ohm's Law — the resistance changes as current or voltage changes. Examples include:

Always check whether a component is ohmic before assuming V = IR gives a constant R value. For non-ohmic components, R = V/I still gives the resistance at that particular operating point, but R is not constant.

🔬 Measuring Current and Voltage in Circuits

Setting up a circuit correctly to measure current and voltage is a core practical skill. Here are the key rules:

Ammeter → always in SERIES. Voltmeter → always in PARALLEL.

Measuring current: Break the circuit at the point where you want to measure current and insert the ammeter into the gap. The ammeter becomes part of the series circuit, so the same current that flows through the component flows through the ammeter. A good ammeter has very low resistance (close to 0 Ω) so it barely affects the circuit.

Measuring voltage: Connect the voltmeter probes to the two points across which you want to measure the potential difference — i.e., in parallel with the component. A good voltmeter has very high resistance (close to ∞ Ω) so negligible current flows through it, meaning it doesn't "steal" current from the main circuit.

Variable resistors (rheostats) are often added to circuits to allow the current to be varied, so that multiple readings of V and I can be taken to plot a V–I (or I–V) characteristic graph. Plotting multiple points and drawing a line of best fit reduces the effect of random errors.

Reading meters accurately: Always note the scale range selected on analogue meters and record values to an appropriate number of significant figures. Digital meters display values directly but always consider their stated uncertainty (typically ±1 in the last digit).

When plotting I–V graphs: place V on the x-axis and I on the y-axis. The gradient = 1/R for an ohmic component.
Example 1: A resistor has a resistance of 15 Ω. A current of 2 A flows through it. Calculate the potential difference across the resistor.
1 Identify the formula: V = I × R
2 Write down the known values: I = 2 A, R = 15 Ω
3 Substitute into the formula: V = 2 × 15
4 Calculate: V = 30 V
Potential difference V = 30 V
Example 2: A 12 V battery is connected to a lamp. The current flowing through the lamp is 0.4 A. Calculate the resistance of the lamp.
1 Identify the formula: We need R, so rearrange V = IR → R = V ÷ I
2 Write down the known values: V = 12 V, I = 0.4 A
3 Substitute into the rearranged formula: R = 12 ÷ 0.4
4 Calculate: R = 30 Ω
Resistance R = 30 Ω
Example 3: A component has a resistance of 220 Ω. The potential difference across it is 11 V. Calculate the current flowing through it.
1 Identify the formula: We need I, so rearrange V = IR → I = V ÷ R
2 Write down the known values: V = 11 V, R = 220 Ω
3 Substitute into the rearranged formula: I = 11 ÷ 220
4 Calculate: I = 0.05 A
Current I = 0.05 A (or 50 mA)
Example 4: A student measures the following values for a resistor: V = 6.0 V, I = 0.30 A. (a) Calculate the resistance. (b) The student then doubles the voltage to 12.0 V. If the resistor is ohmic, what current would you expect?
1 Part (a) — find R: R = V ÷ I = 6.0 ÷ 0.30 = 20 Ω
2 Part (b) — the resistor is ohmic, so R stays constant at 20 Ω
3 Use I = V ÷ R with the new voltage: I = 12.0 ÷ 20 = 0.60 A
4 Check using proportionality: Doubling V → doubles I (direct proportion for ohmic conductor) ✓
(a) R = 20 Ω    (b) I = 0.60 A

Question 1: Which unit is used to measure electric current?

Question 2: A resistor has a potential difference of 9 V across it and a current of 3 A flowing through it. What is its resistance?

Question 3: How must an ammeter be connected in a circuit?

Question 4: Calculate the potential difference across a 47 Ω resistor when a current of 0.2 A flows through it. Type your answer in volts (V).

Question 5: Which of the following components does NOT obey Ohm's Law (i.e., is non-ohmic)?

Challenge 1: A student connects a resistor to a 6 V supply and measures a current of 0.15 A. The student then connects a second identical resistor in series with the first. The supply voltage remains at 6 V.

(a) Calculate the resistance of one resistor.
(b) Calculate the total resistance of the two resistors in series.
(c) Calculate the new current flowing in the circuit.

Challenge 2: The table below shows data collected for a component:

V (V)I (A)R (Ω)
2.00.10?
4.00.16?
6.00.20?
8.00.23?

(a) Calculate the resistance at each voltage.
(b) Is this component ohmic? Justify your answer.
(c) Suggest what component this could be.

Challenge 3: A torch bulb is rated at 3.0 V, 0.5 A.

(a) Calculate the resistance of the bulb at its normal operating conditions.
(b) A student measures the resistance of the cold bulb filament with an ohmmeter and gets 2.4 Ω. Explain why this value is much lower than your answer to (a).
(c) Calculate the charge that flows through the bulb in 5 minutes.

Challenge 4 (Extended): A student wants to determine the resistance of an unknown resistor Rx. She sets up a circuit with a variable power supply, an ammeter in series with Rx, and a voltmeter in parallel with Rx. She varies the voltage and records the following results:

V = 1.5 V, I = 0.075 A  |  V = 3.0 V, I = 0.150 A  |  V = 4.5 V, I = 0.225 A  |  V = 6.0 V, I = 0.300 A

(a) Describe the relationship between V and I for this resistor.
(b) Use any pair of readings to calculate Rx.
(c) Explain one advantage of using multiple readings rather than a single reading to determine resistance.
(d) The voltmeter used has a very low resistance. Explain how this would affect the measurements and what a student should use instead.