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Laws of Indices

Grade 9 · Algebra · Cambridge IGCSE 0580 · Age 13–14

Welcome to Laws of Indices!

An index (or exponent) tells you how many times a base is multiplied by itself. The Laws of Indices are a set of rules that let you simplify, expand, and solve expressions involving powers quickly and reliably. They underpin algebra, equations, surds, and much of IGCSE mathematics.

am means a × a × a × … (m times)  |  Base: a  |  Index: m

There are 9 key laws to master. Each one has a simple justification based on what multiplication really means. Once you understand the why, the rules become easy to remember and apply.

Multiplication Law

am × an = am+n

Division Law

am ÷ an = am−n

Power Law

(am)n = amn

Zero Index

a0 = 1

Negative Index

a−n = 1/an

Fractional Index

a1/n = n√a

General Fraction

am/n = (n√a)m

Bracket Laws

(ab)n and (a/b)n

Solving Equations

2x = 32 → x = ?

The 9 Laws — Quick Reference

LawRuleExample
Multiplicationam × an = am+n23 × 24 = 27 = 128
Divisionam ÷ an = am−n35 ÷ 32 = 33 = 27
Power of Power(am)n = amn(23)4 = 212
Zero Indexa0 = 1 (a ≠ 0)70 = 1, (−3)0 = 1
Negative Indexa−n = 1/an2−3 = 1/8
Fractional Index (root)a1/n = n√a81/3 = ∛8 = 2
Fractional Index (general)am/n = (n√a)m82/3 = (∛8)2 = 4
Bracket — product(ab)n = anbn(2×3)2 = 4×9 = 36
Bracket — quotient(a/b)n = an/bn(2/3)3 = 8/27

1. Multiplication Law: am × an = am+n

Why it works: am means m copies of a multiplied together, and an means n more copies. Put them together and you have m + n copies total.

Proof:
a3 × a4 = (a × a × a) × (a × a × a × a) = a7
Counting: 3 + 4 = 7 factors of a.
am × an = am+n  — add the indices when multiplying same base
Examples:
52 × 53 = 55 = 3125
x4 × x7 = x11
3a2 × 5a3 = 15a5  (multiply coefficients, add indices)
2x3y2 × 4x2y = 8x5y3
Only add indices when the bases are the same. x2 × y3 cannot be simplified further — the bases differ.

2. Division Law: am ÷ an = am−n

Why it works: Division cancels pairs of factors. Each a in the denominator cancels one a in the numerator, leaving m − n factors of a.

Proof:
a5 ÷ a2 = (a×a×a×a×a) / (a×a) = a3
5 − 2 = 3 factors remain.
am ÷ an = am−n  — subtract the indices when dividing same base
Examples:
27 ÷ 23 = 24 = 16
x9 ÷ x4 = x5
12x5 ÷ 4x2 = 3x3  (divide coefficients, subtract indices)
6a4b3 ÷ 2a2b = 3a2b2

3. Power of a Power: (am)n = amn

Why it works: Raising am to the power n means multiplying am by itself n times. By the multiplication law, you add m repeatedly n times: m + m + … + m = mn.

Proof:
(a3)4 = a3 × a3 × a3 × a3 = a3+3+3+3 = a12
Alternatively: 3 × 4 = 12.
(am)n = amn  — multiply the indices for a power of a power
Examples:
(52)3 = 56 = 15625
(x4)5 = x20
(2x3)4 = 24x12 = 16x12
(3a2b)3 = 27a6b3
When a bracket contains a coefficient, raise the coefficient to that power too: (2x3)4 = 24 × x3×4 = 16x12.

4. Zero Index: a0 = 1

Why it works: Use the division law. an ÷ an = an−n = a0. But any number divided by itself is 1. Therefore a0 = 1.

a0 = 1 for any non-zero value of a
70 = 1    1000 = 1    (−5)0 = 1
(x2y3)0 = 1    3x0 = 3×1 = 3  (only x is raised to 0)
Watch out: 3x0 = 3 because only x is raised to the power 0, not the whole term 3x. If the whole term is raised to 0, write it as (3x)0 = 1.

5. Negative Index: a−n = 1/an

Why it works: Using the division law: a2 ÷ a5 = a2−5 = a−3. But also a2/a5 = 1/a3. So a−3 = 1/a3.

a−n = 1/an  — a negative index means "take the reciprocal"
Examples:
2−3 = 1/23 = 1/8
3−2 = 1/9
x−4 = 1/x4
(1/2)−3 = 23 = 8  (reciprocal of 1/2 is 2)
5x−2 = 5/x2
To evaluate a−n with a fraction base: (a/b)−n = (b/a)n. The negative index flips the fraction.

6. Fractional Index (Root): a1/n = n√a

Why it works: If we want a1/n to obey the power law, then (a1/n)n = a1 = a. So a1/n must be the number that gives a when raised to the power n — that is the nth root of a.

a1/n = n√a  — a fractional index of 1/n is the nth root
Examples:
91/2 = √9 = 3
81/3 = ∛8 = 2
161/4 = ⁴√16 = 2
641/2 = 8    271/3 = 3    321/5 = 2
Connection to surds: 21/2 = √2. Fractional indices with denominator 2 are the same as square roots — surds and indices are the same idea expressed differently.

7. General Fractional Index: am/n = (n√a)m

Why it works: am/n = (a1/n)m = (n√a)m by the power law combined with the root law. You can also write it as n√(am), but root first then power is usually easier to compute.

am/n = (n√a)m  — root first (denominator), then power (numerator)
Examples:
82/3 = (∛8)2 = 22 = 4
272/3 = (∛27)2 = 32 = 9
163/4 = (⁴√16)3 = 23 = 8
43/2 = (√4)3 = 23 = 8
323/5 = (⁵√32)3 = 23 = 8
With negative fractional index:
8−2/3 = 1/82/3 = 1/(∛8)2 = 1/4
27−1/3 = 1/∛27 = 1/3
Memory tip: m/n → denominator is the Root, numerator is the Power. Think D.R. → R.P. → Root then Power.

8. Bracket Laws: (ab)n = anbn  and  (a/b)n = an/bn

When a bracket contains a product or quotient and is raised to a power, distribute the index to every factor inside.

(ab)n = anbn    (a/b)n = an/bn
Proof of (ab)n:
(ab)3 = (ab)(ab)(ab) = a·a·a · b·b·b = a3b3
Examples:
(3x)2 = 9x2
(2xy)3 = 8x3y3
(x/2)4 = x4/16
(2a2b)3 = 8a6b3

9. Solving Index Equations: 2x = 32

When solving equations like 2x = 32, rewrite both sides with the same base, then equate the indices.

If ax = ak then x = k  — same base means indices are equal
Example 1: Solve 2x = 32
32 = 25, so 2x = 25 → x = 5
Example 2: Solve 3x = 1/9
1/9 = 1/32 = 3−2, so 3x = 3−2 → x = −2
Example 3: Solve 4x = 8
Write both as powers of 2: 4 = 22, 8 = 23
(22)x = 23 → 22x = 23 → 2x = 3 → x = 3/2
Example 4: Solve 52x−1 = 125
125 = 53, so 2x − 1 = 3 → 2x = 4 → x = 2
Key bases to know: 2, 4, 8, 16, 32, 64 (powers of 2); 3, 9, 27, 81 (powers of 3); 5, 25, 125 (powers of 5); 2, 8, 32 = 21,23,25; 4, 16, 64 = 22,24,26.

10. Simplifying Algebraic Expressions

Apply multiple laws in sequence to simplify complex algebraic expressions with indices.

Example 1: Simplify (2x3y2)3 ÷ (4x2y)
= 8x9y6 ÷ 4x2y  [bracket law]
= 2x7y5  [division law]
Example 2: Simplify 3a2b3 × 2a−1b2
= 6a2+(−1)b3+2
= 6a1b5 = 6ab5
Work systematically: deal with coefficients first, then each variable's index separately using the relevant law.

Example 1 — Evaluate 272/3

Identify: fractional index m/n = 2/3. Root = 3 (cube root), Power = 2.
Root first: ∛27 = 3  (since 33 = 27)
Then power: 32 = 9
Answer: 272/3 = 9

Example 2 — Evaluate 16−3/4

Negative index: 16−3/4 = 1 / 163/4
Root first: ⁴√16 = 2  (since 24 = 16)
Power: 23 = 8, so 163/4 = 8
Negative: 1/8.  Answer: 16−3/4 = 1/8

Example 3 — Simplify (3x2y)3

Apply bracket law: raise each factor to the power 3
33 = 27    (x2)3 = x6    y3 = y3
Answer: (3x2y)3 = 27x6y3

Example 4 — Simplify 4x3y5 × 3x2y−2

Coefficients: 4 × 3 = 12
x terms: x3 × x2 = x3+2 = x5
y terms: y5 × y−2 = y5+(−2) = y3
Answer: 12x5y3

Example 5 — Simplify (8x6) ÷ (2x4)2

Simplify denominator first: (2x4)2 = 4x8
Divide: 8x6 ÷ 4x8 = 2x6−8 = 2x−2
Write without negative index: 2/x2
Answer: 2x−2 = 2/x2

Example 6 — Solve 9x = 27

Common base: 9 = 32 and 27 = 33
Rewrite: (32)x = 33 → 32x = 33
Equate indices: 2x = 3
Answer: x = 3/2

Multiplication Law Visualiser: am × an = am+n

Choose a base and two indices. See the individual groups of factors and their combined count visually.

Choose values and click Visualise.

Index Law Calculator

Evaluate any expression of the form am/n step by step.

Result will appear here.

Index Equation Solver

Solve ax = c by rewriting both sides in the same base.

Result will appear here.

Exercise 1 — Multiplication & Division Law (Numbers)

Use aᵐ × aⁿ = aᵐ⁺ⁿ and aᵐ ÷ aⁿ = aᵐ⁻ⁿ. Give the index of the simplified answer (the power, not the full value).

1. 23 × 24 = 2?   Give the index.

2. 32 × 35 = 3?   Give the index.

3. 56 ÷ 52 = 5?   Give the index.

4. 78 ÷ 73 = 7?   Give the index.

5. 41 × 46 = 4?   Give the index.

6. 210 ÷ 26 = 2?   Give the index.

Exercise 2 — Power of a Power & Zero Index

Use (aᵐ)ⁿ = aᵐⁿ and a⁰ = 1. Give the index of the simplified answer or the integer value.

1. (23)4 = 2?   Give the index.

2. (52)3 = 5?   Give the index.

3. (34)2 = 3?   Give the index.

4. 90 = ?   Give the value.

5. (−7)0 = ?   Give the value.

6. (x5)4 = x?   Give the index.

Exercise 3 — Negative Indices (Evaluate)

Use a⁻ⁿ = 1/aⁿ. Give the answer as a fraction (numerator only, since denominator is given) or as a decimal where indicated.

1. 2−1 = 1/?   Give the denominator.

2. 2−3 = 1/?   Give the denominator.

3. 3−2 = 1/?   Give the denominator.

4. 5−2 = 1/?   Give the denominator.

5. 4−1 = 1/?   Give the denominator.

6. 10−3 = 1/?   Give the denominator.

Exercise 4 — Fractional Indices (Evaluate)

Use a1/n = ⁿ√a and am/n = (ⁿ√a)m. Give the integer value.

1. 91/2 = ?   Give the value.

2. 271/3 = ?   Give the value.

3. 161/4 = ?   Give the value.

4. 82/3 = ?   Give the value.

5. 43/2 = ?   Give the value.

6. 322/5 = ?   Give the value.

Exercise 5 — Solving Index Equations

Solve each equation by writing both sides with the same base. Give the value of x (may be a fraction — enter as a decimal).

1. 2x = 8   → x = ?

2. 2x = 32   → x = ?

3. 3x = 27   → x = ?

4. 3x = 1/9   → x = ?

5. 5x = 125   → x = ?

6. 4x = 8   → x = ? (enter as decimal)

Practice — 20 Questions

Mixed practice covering all Laws of Indices. Read each question carefully and enter the correct value.

1. 24 × 23 = 2?   Give the index.

2. 57 ÷ 53 = 5?   Give the index.

3. (32)5 = 3?   Give the index.

4. 120 = ?   Give the value.

5. 2−4 = 1/?   Give the denominator.

6. 251/2 = ?   Give the value.

7. 641/3 = ?   Give the value.

8. 272/3 = ?   Give the value.

9. 163/4 = ?   Give the value.

10. Solve 2x = 64.   x = ?

11. Solve 3x = 81.   x = ?

12. Solve 5x = 1/25.   x = ?

13. 35 × 3−2 = 3?   Give the index.

14. (24)3 ÷ 28 = 2?   Give the index.

15. 8−1/3 = 1/?   Give the denominator.

16. (1/3)−2 = ?   Give the integer value.

17. 323/5 = ?   Give the value.

18. 45/2 = ?   Give the value.

19. Solve 4x = 32 (write x as a decimal).

20. Solve 9x = 27 (write x as a decimal).

Challenge — 8 Questions

Harder questions involving multiple laws, algebraic expressions, and problem solving. Give numerical answers or index values as instructed.

1. Evaluate 1252/3. Give the integer value.

2. Evaluate 81−3/4 = 1/? Give the denominator.

3. Solve 8x = 2. Give x as a fraction (decimal). Hint: write 8 = 23.

4. Solve 25x = 125. Give x as a decimal. Hint: use base 5.

5. Simplify (4x3)2 ÷ (2x4). Result = k·xp. Give the value of p (the index of x).

6. If a3 = 8, what is a−2? Give the answer as a fraction: 1/? Enter the denominator.

7. Evaluate (27/8)2/3. Result = p/q. Enter the numerator p.

8. Solve 23x−1 = 16. Give the value of x.