Grade 8 Β· Cambridge Lower Secondary Stage 8
Every straight line can be written as y = mx + c where:
Gradient = how steep the line is = change in y Γ· change in x.
Given two points, you can find the equation y = mx + c:
Parallel lines have the same gradient but different y-intercepts.
Perpendicular lines have gradients that multiply to β1.
Two lines meet at one point (unless parallel). Find intersection by solving simultaneously.
State the gradient and y-intercept of: (a) y = 4x β 3 (b) y = β2x + 7 (c) 2y = 6x + 10
Find the gradient of the line through (1, 4) and (5, 12).
Find the equation of the line through (3, 7) and (6, 13).
Line L: y = 4x + 1. Find the equation of: (a) a parallel line through (0, β3) (b) a perpendicular line through (0, 2)
Plot up to two lines y = mx + c on the same axes.
Enter gradients of two lines. Find out their relationship.
y = mβx + cβ and y = mβx + cβ. Find where they meet.
For y = mx + c, give the gradient (m). Even-numbered questions ask for c instead β check question carefully.
Calculate the gradient of the line through the given points.
You are given the gradient and a point on the line. Find the y-intercept c.
Enter the gradient of the parallel or perpendicular line as directed. Use decimals (e.g. β0.5).
Odd questions: give the x-coordinate of intersection. Even questions: give the y-coordinate.