Transformations & Enlargement

Cambridge Lower Secondary Stage 7 β€” Unit 14

Enlargement, similarity, and combined transformations

Animation: triangle enlarged by scale factor 2 from the origin. Lines from O pass through each vertex to show how enlargement works.

What is Enlargement?

An enlargement changes the size of a shape but keeps its angles the same and all sides in the same ratio. The enlarged shape is called the image. The original is called the object.

Every enlargement needs two things:

  • Scale factor (SF) β€” how many times bigger (or smaller)
  • Centre of enlargement β€” the fixed point from which distances are measured
Image distance from centre = SF × Object distance from centre
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SF > 1 β€” Gets Bigger

SF = 2 means every length doubles. SF = 3 means every length triples.

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0 < SF < 1 β€” Gets Smaller

SF = Β½ means every length halves. The image is inside the object.

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Finding the Centre

Draw lines through matching vertices of object and image β€” they all meet at the centre.

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Finding the SF

SF = image side length Γ· object side length. Or: image distance from centre Γ· object distance from centre.

Similar Shapes

Two shapes are similar if one is an enlargement of the other. Similar shapes have:

  • All corresponding angles equal
  • All corresponding sides in the same ratio
Missing side = Known side × Scale Factor  |  SF = image side Γ· object side

To find a missing length: identify the ratio (scale factor) from a pair of known corresponding sides, then multiply.

Combined Transformations

Two transformations applied in sequence. Order matters! Always apply the first transformation, then use that result as the new object for the second transformation.

Common combinations: reflect then enlarge, translate then rotate, enlarge then reflect.

Apply Transformation 1 β†’ Get Image 1 β†’ Apply Transformation 2 β†’ Get Final Image

Key Vocabulary

TermMeaning
ObjectThe original shape before transformation
ImageThe shape after transformation
Scale factorThe multiplier for all lengths
Centre of enlargementThe fixed point from which enlargement is measured
SimilarSame shape, different size (all angles equal, sides in ratio)
CongruentSame shape AND same size (scale factor = 1)

Worked Examples

Example 1 β€” Enlarge by Scale Factor 2 from the Origin

Triangle with vertices A(1,1), B(3,1), C(1,3). Enlarge by SF 2 from centre O(0,0).

Rule: Multiply each coordinate by the scale factor.
A(1,1) → A'(2,2)   [1×2, 1×2]
B(3,1) → B'(6,2)   [3×2, 1×2]
C(1,3) → C'(2,6)   [1×2, 3×2]
Check: Every side of A'B'C' is twice as long. Angles unchanged.

Example 2 β€” Enlarge by Scale Factor Β½ from Centre (4,4)

Square with vertices P(2,2), Q(6,2), R(6,6), S(2,6). Enlarge by SF Β½ from centre C(4,4).

Rule: Find the vector from centre to each vertex, then multiply by SF.
P(2,2): vector from C = (2βˆ’4, 2βˆ’4) = (βˆ’2,βˆ’2). Multiply by Β½ = (βˆ’1,βˆ’1). New point: (4βˆ’1, 4βˆ’1) = P'(3,3)
Q(6,2): vector = (2,βˆ’2) × Β½ = (1,βˆ’1). Q' = (4+1, 4βˆ’1) = Q'(5,3)
R(6,6): vector = (2,2) × Β½ = (1,1). R' = (5,5)
S(2,6): vector = (βˆ’2,2) × Β½ = (βˆ’1,1). S' = (3,5)
Result: The image P'Q'R'S' is half the size, inside the original square.

Example 3 β€” Find Scale Factor and Centre of Enlargement

Object: triangle with vertices A(1,1), B(3,1), C(1,3). Image: A'(βˆ’1,βˆ’1), B'(βˆ’5,βˆ’1), C'(βˆ’1,βˆ’5).

Find SF: Compare corresponding side lengths. AB = 2 units; A'B' = 4 units. SF = 4 Γ· 2 = 2
Find centre: Draw lines through A and A', B and B', C and C'. They all pass through (1,1)... extend the lines.
Line through A(1,1) and A'(βˆ’1,βˆ’1): this is the line y = x. Line through B(3,1) and B'(βˆ’5,βˆ’1): slope = (βˆ’1βˆ’1)/(βˆ’5βˆ’3) = ΒΌ, passes through... checking: all lines meet at O(0,0).
Answer: Enlargement, SF = 2, centre (0,0). Note: negative image means centre is between object and image (or object on far side).

Example 4 β€” Missing Length in Similar Triangles

Triangle ABC is similar to triangle DEF. AB = 6 cm, BC = 8 cm, AC = 10 cm. DE = 9 cm. Find EF.

Step 1: Find the scale factor. AB corresponds to DE (both are the "short" sides). SF = DE Γ· AB = 9 Γ· 6 = 1.5
Step 2: EF corresponds to BC. EF = BC × SF = 8 × 1.5 = 12 cm
Step 3: DF corresponds to AC. DF = 10 × 1.5 = 15 cm
Check: All sides in ratio 6:9 = 8:12 = 10:15 = 2:3. βœ“

Enlargement Explorer

Adjust the scale factor and centre to see how the shape transforms live.

SF = 1.5
Blue = object (fixed triangle), Pink = enlarged image, Orange dot = centre of enlargement. Orange lines show how each vertex is projected.

Try these:

  • Set SF = 2, Centre (0,0) β€” classic enlargement from origin
  • Set SF = 0.5, Centre (0,0) β€” image is half the size
  • Set SF = 2, Centre (2,1) β€” enlargement from a different point
  • Set SF = 1.0 β€” image exactly overlaps object (no change)

Exercise 1 β€” Scale Factor Finder

Each pair of shapes is an enlargement. Find the scale factor. Type your answer (e.g. 2 or 0.5 or 1/3).

Exercise 2 β€” Enlargement on a Grid

Each question shows a shape (blue). Type the coordinates of each vertex of the enlarged image. Use the diagram as reference.

Exercise 3 β€” Similar Shapes: Missing Lengths

Each pair of shapes is similar. Find the missing length. Round to 1 decimal place if needed.

Exercise 4 β€” Centre of Enlargement Finder

Click on the grid where you think the centre of enlargement is. You're correct if you click within 1 grid square.

Exercise 5 β€” Describe the Transformation

Each diagram shows an object and its image. Describe the enlargement fully: type, scale factor, and centre of enlargement.

Exercise 6 β€” Combined Transformations

Apply two transformations in sequence. Type the final vertex coordinates after both transformations.

Practice Questions

20 questions β€” reveal each answer when you're ready.

Challenge Problems

10 harder problems β€” fractional scale factors, complex figures, real-world scale.